24.3049x-3x^2-48=0

Solution for 24.3049x-3x^2-48=0 equation:

24.3049x-3x^2-48=0

a = -3; b = 24.3049; c = -48;
Δ = b2-4ac
Δ = 24.30492-4·(-3)·(-48)
Δ = 14.72816401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24.3049)-\sqrt{14.72816401}}{2*-3}=\frac{-24.3049-\sqrt{14.72816401}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24.3049)+\sqrt{14.72816401}}{2*-3}=\frac{-24.3049+\sqrt{14.72816401}}{-6}
$